I did not change anything
Vamsi
this generated the records as i want perfectly
Now,How do i just pass the requestid and have it create all the records in a differant table as i did with the cursor query i had in my original post. Is that something possible
Thanks much again
Vamsi
this generated the records as i want perfectly
Now,How do i just pass the requestid and have it create all the records in a differant table as i did with the cursor query i had in my original post. Is that something possible
Thanks much again
Vamsi
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://ift.tt/19nLNVq http://ift.tt/1iEAj0c
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles
CAST(.. AS DATE) will only work in SQL Server 2008 and up.For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles
Thanks . will change it
Now,How do i just pass the requestid and have it create all the records in a differant table as i did with the cursor query i had in my original post. Is that something possible
Vamsi
Try
Select s.Requestid + Row_Number() Over(Partition By s.Requestid Order By c.dt) As Requestid,
Cast(c.dt As smalldatetime) As ProductionMonth,
s.assignedanalystid As AssignedAnalyst,
s.frequency As freqcd,
Cast(c.dt As smalldatetime) As EnteredDate,
s.requesttypeid As rptdesc,
s.CustomerName As groupname,
s.Requestid As originalrequestid
INTO NewTable -- create new table on the fly
From @Sample s
Inner Join dbo.Calendar c On c.dt Between s.CompletedDate And DateAdd(month, 1, s.ExpirationDate)
Where (s.frequency = 'Monthly' And c.D = 1)
Or (s.frequency = 'Weekly' And DateDiff(day, s.CompletedDate, c.dt) % 7 = 0 And c.dt > s.CompletedDate And c.dt <= DateAdd(week, 1, s.ExpirationDate))
Or (s.frequency = 'Bi-Weekly' And DateDiff(day, s.CompletedDate, c.dt) % 14 = 0 And c.dt > s.CompletedDate And c.dt <= DateAdd(week, 2, s.ExpirationDate))
AND s.RequestId = @RequestID
Order By originalrequestid, Requestid;
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles
We actually save the requestids in a table called TABLE_KEYS and we increment the requestid in that table
Below is the logic i used in my cursor query to update the TABLE_KEYS .How can i do this in your query
set key_id = key_id + 1
where table_name = 'adhoc'
Vamsi