XML Declaration

These classes would serialize to the XML you want.

public class Job
{
    [XmlElement(Type = typeof(Company))]
    public Company Company { get; set; }
        
    public Location Location { get; set; }  
}

public class Company
{
    [XmlTextAttribute]
    public string Name { get; set; }

    [XmlAttribute]
    public string Active { get; set; }        
}

public class Location
{
    public string City { get; set; }

    [XmlAttribute]
    public int Local { get; set; }
}

so..

List<Job> jobs = new List<Job>();
jobs.Add(new Job() { Company = new Company { Name = "ACME", Active = "Yes" }, Location = new Location() { City = "Hollywood", Local = 1} });
jobs.Add(new Job() { Company = new Company { Name = "Black Mesa", Active = "No" }, Location = new Location() { City = "New Mexico", Local = 3 } });
XmlSerializer x = new XmlSerializer(jobs.GetType(), new XmlRootAttribute("Jobs"));
x.Serialize(Console.Out, jobs);
Console.ReadLine();

will produce..

<?xml version="1.0" encoding="ibm850"?>
<Jobs xmlns:xsi="http://ift.tt/Atvu06; xmlns:xsd="http://ift.tt/FPH52k;
  <Job>
    <Company Active="Yes">ACME</Company>
    <Location Local="1">
      <City>Hollywood</City>
    </Location>
  </Job>
  <Job>
    <Company Active="No">Black Mesa</Company>
    <Location Local="3">
      <City>New Mexico</City>
    </Location>
  </Job>
</Jobs>